3x^2+4y^2-48=0

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Solution for 3x^2+4y^2-48=0 equation:


Simplifying
3x2 + 4y2 + -48 = 0

Reorder the terms:
-48 + 3x2 + 4y2 = 0

Solving
-48 + 3x2 + 4y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '48' to each side of the equation.
-48 + 3x2 + 48 + 4y2 = 0 + 48

Reorder the terms:
-48 + 48 + 3x2 + 4y2 = 0 + 48

Combine like terms: -48 + 48 = 0
0 + 3x2 + 4y2 = 0 + 48
3x2 + 4y2 = 0 + 48

Combine like terms: 0 + 48 = 48
3x2 + 4y2 = 48

Add '-4y2' to each side of the equation.
3x2 + 4y2 + -4y2 = 48 + -4y2

Combine like terms: 4y2 + -4y2 = 0
3x2 + 0 = 48 + -4y2
3x2 = 48 + -4y2

Divide each side by '3'.
x2 = 16 + -1.333333333y2

Simplifying
x2 = 16 + -1.333333333y2

Reorder the terms:
-16 + x2 + 1.333333333y2 = 16 + -1.333333333y2 + -16 + 1.333333333y2

Reorder the terms:
-16 + x2 + 1.333333333y2 = 16 + -16 + -1.333333333y2 + 1.333333333y2

Combine like terms: 16 + -16 = 0
-16 + x2 + 1.333333333y2 = 0 + -1.333333333y2 + 1.333333333y2
-16 + x2 + 1.333333333y2 = -1.333333333y2 + 1.333333333y2

Combine like terms: -1.333333333y2 + 1.333333333y2 = 0.000000000
-16 + x2 + 1.333333333y2 = 0.000000000

The solution to this equation could not be determined.

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